How do you simplify ${(2 x - 3)}^{2} + (x - 5) (x + 5) - (x + 4)$ $(2x - 3) ^ { 2} + ( x - 5) ( x + 5) - ( x + 4)$ ?

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Answer 1 · 2018-04-15T10:09:21

$= 5 x^{2} - 13 x - 20$ $=5x^2-13x-20$

${(2 x - 3)}^{2} = (2 x - 3) (2 x - 3)$ $(2x-3)^2=(2x-3)(2x-3)$

$\Rightarrow$ $=>$ $4 x^{2} - 6 x - 6 x + 9$ $4x^2-6x-6x+9$

$\Rightarrow$ $=>$ $4 x^{2} - 12 x + 9$ $4x^2-12x+9$

$(x - 5) (x + 5) = x^{2} + 5 x - 5 x - 25$ $(x-5)(x+5)=x^2+5x-5x-25$

$\Rightarrow$ $=>$ $= x^{2} - 25$ $=x^2-25$

So if we put these altogether

$[4 x^{2} - 12 x + 9] + [x^{2} - 25] - (x + 4)$ $[4x^2-12x+9]+[x^2-25]-(x +4)$

$= 4 x^{2} - 12 x + 9 + x^{2} - 25 - x - 4$ $=4x^2-12x+9+x^2-25-x-4$

$= 5 x^{2} - 13 x - 20$ $=5x^2-13x-20$

How do you simplify (2x−3)2+(x−5)(x+5)−(x+4)(2x - 3) ^ { 2} + ( x - 5) ( x + 5) - ( x + 4)?