How do you simplify ${(2 x^{3})}^{4}$ $(2x^3)^4$ ?

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Answer 1 · 2016-05-03T14:10:37

I found: $16 x^{12}$ $16x^12$

The power of $4$ $4$ is applied to all the elements inside your brackets so you get:

${(2 x^{3})}^{4} = 2^{4} x^{3 \cdot 4} = 16 x^{12}$ $(2x^3)^4=2^4x^(3*4)=16x^12$

where we can remember the property:
${(x^{m})}^{n} = x^{m \cdot n}$ $(x^m)^n=x^(m*n)$

How do you simplify (2x3)4(2x^3)^4?