How do you simplify $(- 2 x^{3} y^{2}) (- 3 x y^{3})$ $(-2x^3y^2)(-3xy^3)$ ?

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How do you simplify $(- 2 x^{3} y^{2}) (- 3 x y^{3})$ $(-2x^3y^2)(-3xy^3)$ ?

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Answer 1 · 2015-09-30T13:27:09

$6 x^{4} y^{5}$ $6x^(4)y^(5)$

Explanation:

According to the law of indices:
$a^{m} \times a^{n} = a^{m + n}$ $a^mxxa^n=a^(m+n)$

This means that to multiply expressions with the same base, you simply have to add the exponents.

Solution
$(- 2 x^{3} y^{2}) (- 3 x y^{3})$ $(−2x^3y^2)(−3xy^3)$
$= (- 2) \cdot (- 3) \cdot x^{3} \cdot x \cdot y^{2} \cdot y^{3}$ $=(-2)*(-3)*x^3*x*y^2*y^3$
$= 6 \cdot x^{3 + 1} \cdot y^{2 + 3}$ $=6*x^(3+1)*y^(2+3)$
$= 6 x^{4} y^{5}$ $=color(blue)(6x^(4)y^(5))$

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How do you simplify $(- 2 x^{3} y^{2}) (- 3 x y^{3})$ $(-2x^3y^2)(-3xy^3)$ ?

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Explanation:

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How do you simplify $(- 2 x^{3} y^{2}) (- 3 x y^{3})$ $(-2x^3y^2)(-3xy^3)$ ?