How do you simplify ${(- 2 x^{4} y^{3})}^{5}$ $(-2x ^4 y ^3)^5$ ?

Question

1942 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-09T19:19:04

$- 32 x^{20} y^{15}$ $-32x^20y^15$

Use the rule for exponents:

${(a^{m})}^{n} = a^{m \cdot n}$ $(a^m)^n = a^(m*n)$

${(- 2 x^{4} y^{3})}^{5} = (- 2^{5} x^{4 \cdot 5} y^{3 \cdot 5}) = - 32 x^{20} y^{15}$ $(-2x ^4 y ^3)^5=(-2^5x^(4*5)y^(3*5)) = -32x^20y^15$

How do you simplify (-2x ^4 y ^3)^5(−2x4y3)5(-2x ^4 y ^3)^5?