How do you simplify $(2xy^6)^5$ ?

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Answer 1 · 2017-01-29T16:51:56

The answer will be $32x^5y^30$ . Explanation follows...

When you make a power in which the base is another power, the simplifying involves multiplying the exponents. For example

$(x^3)^4= x^(3*4)=x^12$

Here's why:

$x^3 = x*x*x$

so, $(x^3)^4=(x*x*x)*(x*x*x)*(x*x*x)*(x*x*x)$

which, as you can see is nothing more than twelve $x$ 's all multiplied in one product, and that can be written $x^12$ .

Don't forget that is you see no exponent on a base, you are to imagine a $1$ there.

So $(2xy^6)^5=2^5*x^5*(y^6)^5=32x^5y^30$

How do you simplify (2xy^6)^5(2xy^6)^5?