How do you simplify $2 y (3 y) + 16 (y + 2) - 10$ $2y(3y) + 16(y + 2) - 10$ ?

Question

2523 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-05T17:27:57

$= 6 y^{2} + 16 y - 22$ $=6y^2+16y-22$

Start by multiplying out the terms:

$2 y \cdot 3 y = 6 y^{2}$ $2y*3y=6y^2$

$16 (y + 2) = 16 y + 32$ $16(y+2)=16y+32$

Then write:

$6 y^{2} + 16 y + 32 - 10 = 6 y^{2} + 16 y - 22$ $6y^2+16y+32-10=6y^2+16y-22$

How do you simplify 2y(3y)+16(y+2)−102y(3y) + 16(y + 2) - 10?