How do you simplify ${(- 3)}^{2} + 12 \cdot 5$ $(-3)^2+12*5$ ?

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How do you simplify ${(- 3)}^{2} + 12 \cdot 5$ $(-3)^2+12*5$ ?

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Answer 1 · 2015-02-10T13:05:55

I would start from the bracket:
${(- 3)}^{2} = 9$ $(-3)^2=9$
and then the multiplication:
$12 \cdot 5 = 60$ $12*5=60$
And the sum:
$9 + 60 = 69$ $9+60=69$

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How do you simplify ${(- 3)}^{2} + 12 \cdot 5$ $(-3)^2+12*5$ ?

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How do you simplify ${(- 3)}^{2} + 12 \cdot 5$ $(-3)^2+12*5$ ?