How do you simplify $(-3)^2times(-3)^4$ ?

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Answer 1 · 2016-01-17T20:42:24

729

So according to the rules of exponents, two exponents being multiplied that have the same base are added together.
Let me break that down.

$A^B + A^C = A^(B+C)$

So, since $-3=-3$ , we can do this:
$(-3)^2 + (-3)^4 = (-3)^(4+2) = (-3)^6$

And $(-3)^6 =$
$(-3) * (-3) * (-3) * (-3) * (-3) * (-3) =$
$9 * 9 * 9 =$
$81 * 9 =$
$729$

How do you simplify (-3)^2times(-3)^4(-3)^2times(-3)^4?