How do you simplify $- 3 {4 x - 2 [3 x - 4 (x - 1) - 2] - 3} + 7$ $-3 { 4x - 2 [ 3x - 4 ( x - 1 ) -2 ] -3 } +7$ ?

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Answer 1 · 2017-08-11T19:29:37

$= - 18 x + 28$ $= -18x+28$

There are 2 terms. The second term of $7$ $7$ will be added in the last step.

Start by multiplying the innermost bracket and work outwards.

$- 3 {4 x - 2 [3 x - 4 (x - 1) - 2] - 3} + 7$ $-3{4x-2[3xcolor(blue)(-4(x-1))-2]-3}+7$

$= - 3 {4 x - 2 [3 x - 4 x + 4 - 2] - 3} + 7 \leftarrow$ $= -3{4x-2[3xcolor(blue)(-4x+4)-2]-3}+7" "larr$ simplify

$= - 3 {4 x - 2 [- x + 2] - 3} + 7 \leftarrow \times - 2$ $=-3{4xcolor(red)(-2)[-x+2]-3}+7" "larr xx color(red)(-2)$

$= - 3 {4 x + 2 x - 4 - 3} + 7 \leftarrow$ $=-3{4xcolor(red)(+2x-4)-3}+7" "larr$ simplify

$= - 3 {6 x - 7} + 7 \leftarrow \times - 3$ $=color(green)(-3){6x-7}+7" "larr color(green)(xx -3)$

$= - 18 x + 21 + 7$ $=color(green)(-18x+21) +7$

$= - 18 x + 28$ $= -18x+28$

How do you simplify −3{4x−2[3x−4(x−1)−2]−3}+7-3 { 4x - 2 [ 3x - 4 ( x - 1 ) -2 ] -3 } +7?