How do you simplify $\frac{- 3 + 7 i}{1 + 8 i}$ $(-3+7i)/(1+8i)$ ?

Question

How do you simplify $\frac{- 3 + 7 i}{1 + 8 i}$ $(-3+7i)/(1+8i)$ ?

1 Answer

Impact of this question

2214 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-31T08:46:13

See process below

Explanation:

$\frac{- 3 + 7 i}{1 + 8 i} = \frac{(- 3 + 7 i) (1 - 8 i)}{(1 + 8 i) (1 - 8 i)} = \frac{- 3 + 24 i + 7 i + 56}{1 - 64} =$ $(-3+7i)/(1+8i)=((-3+7i)(1-8i))/((1+8i)(1-8i))=(-3+24i+7i+56)/(1-64)=$

$= \frac{53 + 31 i}{- 63} = - \frac{53}{63} - \frac{31}{53} i$ $=(53+31i)/-63=-53/63-31/53i$

Science

Math

Humanities

... and beyond

How do you simplify $\frac{- 3 + 7 i}{1 + 8 i}$ $(-3+7i)/(1+8i)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify −3+7i1+8i(-3+7i)/(1+8i)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify $\frac{- 3 + 7 i}{1 + 8 i}$ $(-3+7i)/(1+8i)$ ?