How do you simplify $(3 + a^{2} + 2 a) + (a^{2} - 8 a + 5)$ $(3+a^2+2a) + (a^2 - 8a +5)$ ?

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How do you simplify $(3 + a^{2} + 2 a) + (a^{2} - 8 a + 5)$ $(3+a^2+2a) + (a^2 - 8a +5)$ ?

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Answer 1 · 2015-10-05T18:15:38

The value of this expression is: $2 a^{2} - 6 a + 8$ $2a^2-6a+8$

Explanation:

$(3 + a^{2} + 2 a) + (a^{2} - 8 a + 5) = 3 + a^{2} + 2 a + a^{2} - 8 a + 5 = 8 + 2 a^{2} - 6 a = 2 a^{2} - 6 a + 8$ $(3+a^2+2a)+(a^2-8a+5)=3+a^2+2a+a^2-8a+5=8+2a^2-6a=2a^2-6a+8$

If there is a + sign in front of an expression in brackets (or there are no sighns), you can skip the brackets without changing the expression.

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How do you simplify $(3 + a^{2} + 2 a) + (a^{2} - 8 a + 5)$ $(3+a^2+2a) + (a^2 - 8a +5)$ ?

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How do you simplify (3+a2+2a)+(a2−8a+5) (3+a^2+2a) + (a^2 - 8a +5)?

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How do you simplify $(3 + a^{2} + 2 a) + (a^{2} - 8 a + 5)$ $(3+a^2+2a) + (a^2 - 8a +5)$ ?