How do you simplify $3/(cosy-siny)-2/(sin^2y-cos^2y)$ ?

Question

2986 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-05T15:20:34

$=>(-3siny - 3cosy - 2)/((siny + cosy)(siny - cosy)$

$=>3/(cosy - siny) - 2/((siny + cosy)(siny - cosy))$

$=>-3/(siny - cosy) - 2/((siny + cosy)(siny - cosy))$

Put on a common denominator:

$=>-(3(siny + cosy))/((siny - cosy)(siny + cosy)) - 2/((siny + cosy)(siny - cosy))$

$=>(-3siny - 3cosy - 2)/((siny + cosy)(siny - cosy)$

As far as I can see, you can't simplify further.

Hopefully this helps!

How do you simplify 3/(cosy-siny)-2/(sin^2y-cos^2y)3/(cosy-siny)-2/(sin^2y-cos^2y)?