How do you simplify $[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]$ ?

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Answer 1 · 2016-12-28T14:42:06

$[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]=(5-2i)x^2+(-1+i)x+(7+i)$

$[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]$

= ${(3+i)-(-2+3i)}x^2+{-i-(1-2i)}x+{4+i-(-3)]$

= ${3+i+2-3i}x^2+{-i-1+2i}x+{4+i+3]$

= $(5-2i)x^2+(-1+i)x+(7+i)$

How do you simplify [(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3][(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]?