How do you simplify $- 3 [(x - 2) + 5 (x - 2)]$ $-3[(x-2) + 5(x-2)]$ ?

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Answer 1 · 2017-01-31T23:36:35

See the entire simplification process below:

First, expand the terms within parenthesis within the brackets. Be sure to manage the signs of the individual terms correctly:

$- 3 [(x - 2) + 5 (x - 2)] \to - 3 [x - 2 + 5 x - 10]$ $-3[(x - 2) + 5(x - 2)] -> -3[x - 2 + 5x - 10]$

Next group and combine like terms within the brackets:

$- 3 [x - 2 + 5 x - 10] \to - 3 [x + 5 x - 2 - 10] \to - 3 [6 x - 1]$ $-3[x - 2 + 5x - 10] -> -3[x + 5x - 2 - 10] -> -3[6x - 1]$

Now, multiple each term within the brackets by $- 3$ $-3$ :

$- 3 [6 x - 1] \to (- 3 \times 6 x) + (- 3 \times - 1) \to$ $-3[6x - 1] -> (-3 xx 6x) + (-3 xx -1) ->$

$- 18 x + 3$ $-18x + 3$ or $3 - 18 x$ $3 - 18x$

How do you simplify −3[(x−2)+5(x−2)] -3[(x-2) + 5(x-2)]?