How do you simplify $- 3 a^{2} b (9 a^{2} - 4 b^{2})$ $-3a^2b(9a^2-4b^2)$ ?

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How do you simplify $- 3 a^{2} b (9 a^{2} - 4 b^{2})$ $-3a^2b(9a^2-4b^2)$ ?

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Answer 1 · 2014-10-30T01:00:54

In order to simplify $- 3 a^{2} b (9 a^{2} - 4 b^{2})$ $-3a^2b(9a^2-4b^2)$ you would use the distributive property and multiply $- 3 a^{2} b$ $-3a^2b$ by each of the terms in the parenthesis.
$- 3 a^{2} b (9 a^{2})$ $-3a^2b(9a^2)$ - $- 3 a^{2} b (4 b^{2})$ $-3a^2b(4b^2)$

$(a^{2}) (a^{2})$ $(a^2)(a^2)$ = (a)(a)(a)(a) = $a^{4}$ $a^4$ $(b) (b^{2})$ $(b)(b^2)$ = (b)(b)(b) = $b^{3}$ $b^3$

$- 27 a^{4} b - (- 12 a^{2} b^{3})$ $-27a^4b - (-12a^2b^3)$

Simplify the signs.

$- 27 a^{4} b + 12 a^{2} b^{3}$ $-27a^4b + 12a^2b^3$

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How do you simplify $- 3 a^{2} b (9 a^{2} - 4 b^{2})$ $-3a^2b(9a^2-4b^2)$ ?

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How do you simplify −3a2b(9a2−4b2)-3a^2b(9a^2-4b^2)?

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How do you simplify $- 3 a^{2} b (9 a^{2} - 4 b^{2})$ $-3a^2b(9a^2-4b^2)$ ?