How do you simplify (3bc)^4(3bc)4?

1 Answer
Nov 11, 2015

81 b^4 c^481b4c4

Explanation:

What does (3bc)^4(3bc)4 mean?

Basically, x^4 = x * x * x * xx4=xxxx, so in your case, it's

(3bc) ^4 = (3bc) * (3bc) * (3bc) * (3bc)(3bc)4=(3bc)(3bc)(3bc)(3bc)

As you can multiply in any order your wish, you can drop the parenthesis and "group" the 33, the bb and the cc like follows:

(3bc) ^4 = (3bc) * (3bc) * (3bc) * (3bc)(3bc)4=(3bc)(3bc)(3bc)(3bc)
= 3 * 3 * 3 * 3 * b * b * b * b * c * c * c * c = 3^4 * b^4 * c^4=3333bbbbcccc=34b4c4

Now, the only thing left to do is computing 3^434:

3^4 = 9^2 = 8134=92=81

So, your solution is 81 b^4 c^481b4c4.