How do you simplify $(3 e^{x}) (2 e^{4} x)$ $(3e^x)(2e^4x)$ ?

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Answer 1 · 2015-04-08T23:32:38

I would try multiplying as:
$3 \cdot 2 e^{x} \cdot e^{4} \cdot x = 6 x e^{x + 4}$ $3*2e^x*e^4*x=6xe^(x+4)$

I am not sure you can go beyond this...

Answer 2 · 2015-04-08T23:35:17

Remember $(a^{m}) \cdot (a^{n}) = (a^{m + n})$ $(a^m)*(a^n) = (a^(m+n))$

and $(a b) \cdot (c d e)$ $(ab) * (cde)$ can be re-arranged as $(a c) \cdot (b d) \cdot (e)$ $(ac) * (bd) * (e)$

Therefore
$(3 e^{x}) (2 e^{4} x)$ $(3e^x)(2e^4x)$

$= (3 \times 2) (e^{x + 4}) (x)$ $= (3xx2)(e^(x+4))(x)$

$= 6 e^{x + 4} x$ $=6e^(x+4)x$

How do you simplify (3ex)(2e4x)(3e^x)(2e^4x)?