How do you simplify $- 3 \sqrt{180 h^{4}}$ $-3sqrt(180h^4)$ ?

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Answer 1 · 2018-04-03T15:58:48

$- 18 h^{2} \sqrt{5}$ $-18h^2sqrt5$

Take out the perfect squares from the radical

$- 3 \sqrt{180 h^{4}}$ $-3sqrt(180h^4)$

$- 3 \sqrt{36 \cdot 5 \cdot h^{2} \cdot h^{2}} \to$ $-3sqrt(36*5*h^2*h^2) rarr$ 36, $h^{2}$ $h^2$ are perfect squares

$- 3 \cdot 6 \cdot h \cdot h \sqrt{5}$ $-3*6*h*hsqrt5$

$- 18 \cdot h^{2} \sqrt{5}$ $-18*h^2sqrt5$

$- 18 h^{2} \sqrt{5}$ $-18h^2sqrt5$

How do you simplify −3√180h4-3sqrt(180h^4)?