How do you simplify (3x^2-3x-6)/(x^2-4)?
1 Answer
May 12, 2018
Explanation:
"factorise the numerator/denominator and "
"cancel any common factors"
color(magenta)"factor numerator"
"take out a "color(blue)"common factor "3
rArr3(x^2-x-2)
"the factors of - 2 which sum to - 1 are - 2 and + 1"
=3(x-2)(x+1)
color(magenta)"factor denominator"
x^2-4" is a "color(blue)"difference of squares"
•color(white)(x)a^2-b^2=(a-b)(a+b)
rArrx^2-4=x^2-2^2=(x-2)(x+2)
rArr(3x^2-3x-6)/(x^2-4)
=(3cancel((x-2))(x+1))/(cancel((x-2))(x+2))
=(3(x+1))/(x+2)
"with restriction "x!=-2