How do you simplify $(-3x^2y^3)^4$ ?

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Answer 1 · 2016-09-27T10:38:10

$81x^8y^12$

Recall: two of the laws of indices:

$(x^p)^q = x^(pq)" "larr$ (multiply the indices)

$(xy)^p = x^p y^p" "larr$ (each factor is raised to the power)

Apply the laws to each factor separately

$(-3x^2y^3)^4 = (-3)^4 xx (x^(2))^4 xx y^3)^4$

= $+81 xx x^8 xx y^12$

= $81x^8y^12$

How do you simplify (-3x^2y^3)^4(-3x^2y^3)^4?