How do you simplify $\frac{3 x y^{4}}{2 x^{5} y} \cdot \frac{6 x^{- 3} y^{2}}{4 y}$ $(3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)$ ?

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How do you simplify $\frac{3 x y^{4}}{2 x^{5} y} \cdot \frac{6 x^{- 3} y^{2}}{4 y}$ $(3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)$ ?

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Answer 1 · 2016-07-08T16:50:34

$\frac{9 y^{4}}{4 x^{7}}$ $(9y^4)/(4x^7)$

Explanation:

remember:

$a^{b} \cdot a^{c} = a^{b + c}$ $a^b * a^c = a^(b+c)$

work

$\frac{3 x y^{4}}{2 x^{5} y} \cdot \frac{6 x^{- 3} y^{2}}{4 y}$ $(3xy^4)/(2x^5y) * (6x^-3y^2)/(4y)$

Simplify by dividing out factors in the top and bottom

$\frac{3 y^{3}}{2 x^{4}} \cdot \frac{3 x^{- 3} y}{2}$ $(3y^3)/(2x^4) * (3x^-3y)/(2)$

Now change the $x^{- 3}$ $x^-3$ into $\frac{1}{x^{3}}$ $1/x^3$ and bring it into the denominator since anything to a negative power is one over that number to the positive exponent

$\frac{3 y^{3}}{2 x^{4}} \cdot \frac{3 y}{2 x^{3}}$ $(3y^3)/(2x^4) * (3y)/(2x^3)$

Now we can multiply

$\frac{3 y^{3} \times 3 y}{2 x^{4} \times 2 x^{3}}$ $(3y^3times3y)/(2x^4times2x^3)$

And simplify

$\frac{9 y^{4}}{4 x^{7}}$ $(9y^4)/(4x^7)$

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How do you simplify $\frac{3 x y^{4}}{2 x^{5} y} \cdot \frac{6 x^{- 3} y^{2}}{4 y}$ $(3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)$ ?

1 Answer

Explanation:

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Explanation:

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How do you simplify $\frac{3 x y^{4}}{2 x^{5} y} \cdot \frac{6 x^{- 3} y^{2}}{4 y}$ $(3xy^4)/(2x^5y) *( 6x^-3y^2)/(4y)$ ?