How do you simplify $(4 - z) (- 1)$ $(4-z)(-1)$ ?

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Answer 1 · 2016-04-29T21:19:55

so $(4 - z) (- 1) = z - 4$ $(4-z)(-1)=z-4$

Multiply everything inside the bracket by negative 1

Note: negative times negative is positive

When multiplying, if the signs are different that the product is negative.

$(- 1) \times 4 = - 4$ $(-1)xx4 = -4$
$(- 1) \times (- z) = + z$ $(-1)xx(-z)=+z$

so $(4 - z) (- 1) = z - 4$ $(4-z)(-1)=z-4$

How do you simplify (4−z)(−1)(4-z)(-1)?