How do you simplify $4{z-6(r-5)+8[z-2r+3(r-1)]}$ ?

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Answer 1 · 2017-02-20T19:48:30

$= 36z+8r+24$

This is all one long term, but there are 2 terms in the brackets.
Start by simplifying the innermost brackets.

$4{z-6(color(red)(r-5))+8[z-2r+3color(blue)((r-1))]}$

They are unlike terms, so use the distributive law .

$=4{z color(red)(-6r+30)+8[z-2rcolor(blue)(+3r-3)]}" "larr$ simplify

$=4{z -6r+30color(forestgreen)(+8[z+r-3])}$

$=4{z -6r+30color(forestgreen)(+8z+8r-24)}" "larr$ simplify

$=4{9z+2r+6}" "larr xx 4$

$= 36z+8r+24$

How do you simplify 4{z-6(r-5)+8[z-2r+3(r-1)]}4{z-6(r-5)+8[z-2r+3(r-1)]}?