How do you simplify $4 a^{2} c (2 a - 5)$ $4a^2c (2a - 5)$ ?

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Answer 1 · 2018-01-12T22:41:51

$4 a^{2} c (2 a - 5) = 8 a^{3} - 20 a^{2} c$ $4a^2c(2a-5)=color(blue)(8a^3-20a^2c$

Simplify.

$4 a^{2} c (2 a - 5)$ $4a^2c(2a-5)$

Expand using the distributive property: $a (b + c) = a b + a c$ $a(b+c)=ab+ac$

$4 a^{2} c (2 a - 5) =$ $4a^2c(2a-5)=$

$4 a^{2} c \times 2 a - 4 a^{2} c \times - 5$ $4a^2cxx2a-4a^2cxx-5$

Apply the product rule: $b^{m} \times b^{n} = b^{m + n}$ $b^mxxb^n=b^(m+n)$

(No exponent is understood to be $1$ $1$ .

$4 \times 2 a^{2 + 1} c - 4 a^{2} c \times - 5$ $4xx2a^(2+1)c-4a^2cxx-5$

Simplify.

$8 a^{3} - 4 a^{2} c \times 5$ $8a^3-4a^2cxx5$

Expand.

$8 a^{3} - 20 a^{2} c$ $8a^3-20a^2c$

How do you simplify 4a^2c (2a - 5)4a2c(2a−5)4a^2c (2a - 5)?