How do you simplify $4 r^{6} s \cdot 7 r^{3} s^{5}$ $4r^6s*7r^3s^5$ ?

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Answer 1 · 2018-04-13T18:28:17

Let's factor out the $r$ $r$ s and $s$ $s$ so we can see this more clearly

$(s \times s^{5}) \times (r^{6} \times r^{3}) \times (4 \times 7)$ $(s xx s^5) xx (r^6 xx r^3) xx (4 xx 7)$

When you multiply numbers with the same bases, we add the exponents:

$s^{1 + 5} \times r^{6 + 3} \times 28$ $s^(1+5) xx r^(6+3) xx 28$

$28 s^{6} r^{9}$ $28s^6r^9$

How do you simplify 4r^6s*7r^3s^54r6s⋅7r3s54r^6s*7r^3s^5?