Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you simplify $- 4 \sqrt{10} + 6 \sqrt{40}$ $-4sqrt10+6sqrt40$ ?

1 Answer

Jul 8, 2015

$- 4 \sqrt{10} + 6 \sqrt{4} = 8 \sqrt{10}$ $-4sqrt(10)+6sqrt(4) = 8sqrt(10)$

Explanation:

$\sqrt{40} = \sqrt{4} \cdot \sqrt{10} = 2 \sqrt{10}$ $sqrt(40) = sqrt(4)*sqrt(10) = 2sqrt(10)$
So
$6 \sqrt{40} = 6 \cdot 2 \sqrt{10} = 12 \sqrt{10}$ $6sqrt(40) = 6*2sqrt(10) = 12 sqrt(10)$

and
$- 4 \sqrt{10} + 6 \sqrt{10}$ $-4sqrt(10)+6sqrt(10)$

$XXXX$ $color(white)("XXXX")$ $= - 4 \sqrt{10} + 12 \sqrt{10}$ $=-4sqrt(10)+12sqrt(10)$

$XXXX$ $color(white)("XXXX")$ $= (- 4 + 12) (\sqrt{10})$ $=(-4+12)(sqrt(10))$

$XXXX$ $color(white)("XXXX")$ $= 8 \sqrt{10}$ $=8sqrt(10)$

Related questions

See all questions in Addition and Subtraction of Radicals

Impact of this question

1672 views around the world

You can reuse this answer
Creative Commons License