How do you simplify ${(4 w^{- 6} x^{2})}^{2}$ $(4w^-6x^2)^2$ ?

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Answer 1 · 2016-04-28T16:08:05

$= \frac{16 x^{4}}{w^{12}}$ $= color(blue)((16 x^(4)) / color(blue)( w^(12)$

${(4 w^{- 6} x^{2})}^{2}$ $(4w^-6x^2)^2$

${(4 w^{- 6} x^{2})}^{2} = 4^{2} \cdot w^{(- 6 \cdot 2)} \cdot x^{(2 \cdot 2)}$ $(4w^-6x^2)^2 = 4^2 * w^((-6 * 2 )) * x^((2 * 2))$

$= 16 w^{- 12} x^{4}$ $= 16 color(blue)(w^(-12)) x^(4)$

$= \frac{16 x^{4}}{w^{12}}$ $= (16 x^(4)) / color(blue)( w^(12)$

$= \frac{16 x^{4}}{w^{12}}$ $= color(blue)((16 x^(4)) / color(blue)( w^(12)$

How do you simplify (4w^-6x^2)^2(4w−6x2)2(4w^-6x^2)^2?