How do you simplify $5 x^{2} \cdot 2 x^{5}$ $5x^2 * 2x^5$ leaving only positive exponents?

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Answer 1 · 2016-04-14T21:46:16

$10 x^{7}$ $10x^7$

Since multiplication is commutative, this can be rearranged and written as

$(5 \cdot 2) (x^{2} \cdot x^{5})$ $(5*2)(x^2*x^5)$

Multiply $5$ $5$ and $2$ $2$ to get $10$ $10$ , and recall the rule for multiplying exponential terms with the same base:

$x^{a} \cdot x^{b} = x^{a + b}$ $x^a*x^b=x^(a+b)$

Thus, we see the expression equals

$10 x^{2 + 5} = 10 x^{7}$ $10x^(2+5)=10x^7$

How do you simplify 5x^2 * 2x^5 5x2⋅2x55x^2 * 2x^5 leaving only positive exponents?