How do you simplify $5 x y - 6 x^{2} y^{2} + 4 x^{2} y^{2} - 2 x y$ $5xy - 6x^2y^2 + 4x^2y^2 - 2xy$ ?

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Answer 1 · 2017-06-13T03:27:06

See a solution process below:

First, group and combine like terms:

$5 x y - 6 x^{2} y^{2} + 4 x^{2} y^{2} - 2 x y \Rightarrow$ $5xy - 6x^2y^2 + 4x^2y^2 - 2xy =>$

$- 6 x^{2} y^{2} + 4 x^{2} y^{2} + 5 x y - 2 x y \Rightarrow$ $-6x^2y^2 + 4x^2y^2 + 5xy - 2xy =>$

$(- 6 + 4) x^{2} y^{2} + (5 - 2) x y \Rightarrow$ $(-6 + 4)x^2y^2 + (5 - 2)xy =>$

$- 2 x^{2} y^{2} + 3 x y$ $-2x^2y^2 + 3xy$

Now, factor an $x y$ $xy$ out of each term:

$(x y \cdot - 2 x y) + (3 \cdot x y) \Rightarrow$ $(xy * -2xy) + (3 * xy) =>$

$x y (- 2 x y + 3)$ $xy(-2xy + 3)$

Answer 2 · 2017-06-13T03:32:45

$- x y (2 x y - 3)$ $-xy(2xy-3)$

You would collect equal variables together

$(5 x y - 2 x y) + (- 6 x^{2} y^{2} + 4 x^{2} y^{2})$ $(5xy - 2xy)+(-6x^2y^2 + 4x^2y^2)$

Simplify it

$5 x y - 2 x y = 3 x y$ $5xy - 2xy = 3xy$
$- 6 x^{2} y^{2} + 4 x^{2} y^{2} = - 2 x^{2} y^{2}$ $-6x^2y^2 + 4x^2y^2 = -2x^2y^2$

$3 x y - 2 x^{2} y^{2}$ $3xy -2x^2y^2$

Factorise it by taking a common factor which is $- x y$ $-xy$

$- x y (2 x y - 3)$ $-xy(2xy-3)$

How do you simplify 5xy - 6x^2y^2 + 4x^2y^2 - 2xy5xy−6x2y2+4x2y2−2xy 5xy - 6x^2y^2 + 4x^2y^2 - 2xy?