How do you simplify (6-3i)+(5+4i)(63i)+(5+4i)?

1 Answer
Oct 5, 2016

11+i11+i

Explanation:

Summing complex numbers is a piece of cake!

Every complex number has the form z=color(red)(a)+color(blue)(b)iz=a+bi, where aa and bb are real numbers (the real part and the imaginary part of zz) and ii is the imaginary unit.

To sum two complex numbers, you simply need to sum the real and complex numbers together! So:

(color(red)6-color(blue)3i)+(color(red)5+color(blue)4i) =color(red)6+color(red)5-color(blue)3i+color(blue)4i =color(red)11+(color(blue)(-3+4))i =color(red)11+i(63i)+(5+4i)=6+53i+4i=11+(3+4)i=11+i