How do you simplify $6 (d - 8)$ $6(d - 8)$ ?

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Answer 1 · 2018-03-13T00:36:29

6d-48

You have to distribute the 6 to each of the values inside:
$6 (d - 8)$ $6(d-8)$
$6 \cdot d + 6 \cdot (- 8)$ $6*d+6*(-8)$
$= 6 d + (- 48)$ $=6d+(-48)$

Since adding a negative number is the same as subtracting a positive number, you can rewrite it as:

$6 d - 48$ $6d-48$

How do you simplify 6(d - 8)6(d−8)6(d - 8)?