How do you simplify $6b - 4 – 5b^2 – b^2 – 7$ ?

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Answer 1 · 2016-03-12T19:42:08

$-6b^2+6b-11$

Collecting like terms

$(-5b^2-b^2)+(6b)+(-4-7)$

$(-6b^2)+(6b)+(-11)$

Remember that + and - together make - so +(-11) = -11

$-6b^2+6b-11$

How do you simplify 6b - 4 – 5b^2 – b^2 – 76b - 4 – 5b^2 – b^2 – 7?