How do you simplify -6i^3+i^2? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Konstantinos Michailidis Sep 19, 2016 6*i-1 Explanation: We know that i^2=-1 i^3=i^2*i=-i Hence -6*i^3+i^2=-6*(-i)-1=6*i-1 Answer link Related questions How do I use DeMoivre's theorem to find (1+i)^5? How do I use DeMoivre's theorem to find (1-i)^10? How do I use DeMoivre's theorem to find (2+2i)^6? What is i^2? What is i^3? What is i^4? How do I find the value of a given power of i? How do I find the nth power of a complex number? How do I find the negative power of a complex number? Write the complex number i^17 in standard form? See all questions in Powers of Complex Numbers Impact of this question 2047 views around the world You can reuse this answer Creative Commons License