How do you simplify $6 t (2 t - 3) - 5 (2 t^{2} + 9 t - 3)$ $6t(2t-3)-5(2t^2+9t-3)$ ?

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Answer 1 · 2017-02-17T18:53:22

$2 t^{2} - 63 t + 15$ $2t^2-63t+15$

In order to simplify we can get rid of the brackets by using the distributive law.

$6 t (2 t - 3) - 5 (2 t^{2} + 9 t - 3)$ $6t(2t-3)-5(2t^2+9t-3)$

$= 12 t^{2} - 18 t - 10 t^{2} - 45 t + 15$ $=12t^2-18t-10t^2-45t+15" "$ now add like terms

$= 2 t^{2} - 63 t + 15$ $=2t^2-63t+15$

How do you simplify 6t(2t−3)−5(2t2+9t−3)6t(2t-3)-5(2t^2+9t-3)?