How do you simplify $(6y^2+4y-3)+(3y^2+2)$ ?

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Answer 1 · 2016-02-24T12:02:53

$9y^2 + 4y - 1$

By writing the expression without brackets and 'collecting' like terms.

$6y^2 + 4y - 3 + 3y^2 + 2 = 9y^2 + 4y - 1$

How do you simplify (6y^2+4y-3)+(3y^2+2)(6y^2+4y-3)+(3y^2+2)?