How do you simplify (7^4)^3(74)3?

2 Answers
Jan 7, 2017

7^(12)712

Explanation:

Using the color(blue)"law of exponents"law of exponents

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^mxxa^n=a^(m+n))color(white)(2/2)|)))
which can be extended to the product of more than 2 terms.

rArr(7^4)^3=7^4xx7^4xx7^4

=7^(4+4+4)=7^(12)

Note that the exponent 12, is also obtained by color(blue)"multiplying" 3 and 4 together. This leads us to a further law of exponents.

"That is " color(red)(bar(ul(|color(white)(2/2)color(black)((a^m)^n=a^(mn))color(white)(2/2)|)))

rArr(7^4)^3=7^(4xx3)=7^(12)

Jan 7, 2017

(7^4)^3 = 7^12

Explanation:

Note that if a is any number and m, n are positive integers then:

(a^m)^n=overbrace(a^mxxa^mxx...xxa^m)^"n times"

color(white)((a^m)^n)=overbrace(overbrace(axxaxx...xxa)^"m times"xxoverbrace(axxaxx...xxa)^"m times"xx...xxoverbrace(axxaxx...xxa)^"m times")^"n times"

color(white)((a^m)^n)=overbrace(axxaxx...xxa)^"mn times"

color(white)((a^m)^n)=a^(mn)

So in our example:

(7^4)^3 = 7^(4*3) = 7^12