How do you simplify $(- 7 c^{3} d^{4}) (4 c d^{3})$ $(-7c^3d^4)(4cd^3)$ ?

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Answer 1 · 2017-02-09T14:01:47

See the entire simplification process below:

First, rewrite the equation to group like terms:

$(- 7 \times 4) (c^{3} \times c) (d^{4} \times d^{3})$ $(-7 xx 4)(c^3 xx c)(d^4 xx d^3)$

Use the two rules of exponents to complete the simplification:

$a = a^{1}$ $a = a^color(red)(1)$

$x^{a} \times x^{b} = x^{a + b}$ $x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) +color(blue)(b))$

$(- 7 \times 4) (c^{3} \times c^{1}) (d^{4} \times d^{3}) \to$ $(-7 xx 4)(c^3 xx c^color(blue)(1))(d^4 xx d^3) ->$

$- 28 c^{3 + 1} d^{4 + 3} \to$ $-28c^(3 + 1)d^(4 + 3) ->$

$- 28 c^{4} d^{7}$ $-28c^4d^7$

How do you simplify (-7c^3d^4)(4cd^3)(−7c3d4)(4cd3)(-7c^3d^4)(4cd^3)?