How do you simplify $(7x^2yz)^3$ ?

Question

1978 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-18T08:46:09

$=343x^6y^3z^3$

The index shown applies to all the factors inside the bracket.

Recall the laws of indices:

$(xyz)^m = x^my^mz^m" and "(x^m)^n = x^(mn)$

Using both of these laws gives:

$(7x^2yz)^3 = 7^3x^6y^3z^3$

While $7^3$ is acceptable, you might want to find the actual value.

$7^3x^6y^3z^3$

$=343x^6y^3z^3$

How do you simplify (7x^2yz)^3(7x^2yz)^3?