How do you simplify $7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy (x^2 + y) - 11 xy^2 (x^2 -1)$ ?

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Answer 1 · 2017-08-02T11:35:38

By arranging $x y (7 x^{2} + 18 y^{2} - 11 x^{2} y)$ $xy (7x^2 + 18y^2 - 11x^2y)$

Your equation becomes
$7 x^{3} y + 7 x y^{2} - 11 x^{3} y^{2} + 11 x y^{2}$ $7x^3y + 7xy^2 - 11x^3y^2 + 11xy^2$

after getting rid of parantheses

$= 7 x^{3} y + 18 x y^{3} - 11 x^{3} y^{2}$ $=7x^3y + 18xy^3 - 11x^3y^2$

Use a common term (xy) to simplify

$= x y (7 x^{2} + 18 y^{2} - 11 x^{2} y)$ $=xy (7x^2 + 18y^2 - 11x^2y)$

How do you simplify 7xy (x^2 + y) - 11 xy^2 (x^2 -1)7xy(x2+y)−11xy2(x2−1)7xy (x^2 + y) - 11 xy^2 (x^2 -1)?