How do you simplify $- 8 (- 11 b) (- c)$ $-8(-11b)(-c)$ ?

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Answer 1 · 2017-02-20T15:47:43

See the entire simplification process below:

We can rewrite this expression as:

$(- 8 \times - 11) (b \times - c) = 88 \times - b c =$ $(-8 xx -11)(b xx -c) = 88 xx -bc =$

$- 88 b c$ $-88bc$

How do you simplify -8(-11b)(-c)−8(−11b)(−c)-8(-11b)(-c)?