How do you simplify $8(-7)^4 * 4(-7)^11$ ?

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Answer 1 · 2018-05-22T19:08:33

$32 xx (-7)^15$
$=-1.5192 xx 10^14$

$8(-7)^4 xx 4(-7)^11$ is all one term with four factors multiplied.

You can re-arrange them.
$8 xx 4 xx (-7)^4 xx (-7)^11$

$=32 xx (-7)^15" "larr$ add the indices of like bases.

If you simplify this further you get a really big number. It will be negative because the index is an odd number.

$=-1.5192 xx 10^14$

How do you simplify 8(-7)^4 * 4(-7)^118(-7)^4 * 4(-7)^11?