How do you simplify $(8n^4-6n^2-4)-(6n^2+4-n^4)+(2n^2+3n^4-4-2n)$ ?

Question

1664 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-14T20:14:55

$12n^4 - 10n^2 - 2n - 12$

Step 1) Eliminate all of the parenthesis ensuring you handle all signs correctly:

$8n^4 - 6n^2 - 4 - 6n^2 - 4 + n^4 + 2n^2 + 3n^4 - 4 - 2n$

Step 2) Combine like terms:

$8n^4 + n^4 + 3n^4 - 6n^2 - 6n^2 + 2n^2 - 2n - 4 - 4 - 4$

Step 3) Combine like terms:

$(8 + 1 + 3)n^4 + (-6 - 6 + 2)n^2 - 2n - 12$

$12n^4 - 10n^2 - 2n - 12$

How do you simplify (8n^4-6n^2-4)-(6n^2+4-n^4)+(2n^2+3n^4-4-2n)(8n^4-6n^2-4)-(6n^2+4-n^4)+(2n^2+3n^4-4-2n)?