How do you simplify $(8 x^{2} - 9 x - 1) - (- 6 x^{2} + 4 x - 8)$ $( 8x^2 -9x - 1) - ( -6x^2 + 4x - 8 )$ ?

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Answer 1 · 2016-01-31T11:09:19

See explanation..

$(8 x^{2} - 9 x - 1) - (- 6 x^{2} + 4 x - 8)$ $(8x^2-9x-1)-(-6x^2+4x-8)$

Always remember that if we need to subtract we need to change the signs.

$\to 8 x^{2} - 9 x - 1 + 6 x^{2} + 4 x - 8$ $rarr8x^2-9x-1+6x^2+4x-8$

$\to 14 x^{2} - 9 x - 1 + 4 x - 8$ $rarr14x^2-9x-1+4x-8$

$\to 14 x^{2} - 5 x - 1 - 8$ $rarr14x^2-5x-1-8$

$\to 14 x^{2} - 5 x - 9$ $rarr14x^2-5x-9$

Factor

$\to (14 x + 9) (x - 1)$ $rarr(14x+9)(x-1)$

See the video for better explanation:

How do you simplify (8x2−9x−1)−(−6x2+4x−8)( 8x^2 -9x - 1) - ( -6x^2 + 4x - 8 )?