How do you simplify $(9 – 6i) – (12 + 2i)$ ?

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Answer 1 · 2016-01-14T10:12:31

simplification is - 3 - 8i

To add or subtract complex numbers , add/subtract the real parts and add/subtract the coefficients of the imaginary parts.

for ( a + bi ) + (c + di ) = ( a + c ) + (b + d ) i

in this question (9 - 6i ) - (12 + 2i ) = (9 - 12 ) +( - 6 - 2 )i = - 3 - 8i

How do you simplify (9 – 6i) – (12 + 2i)(9 – 6i) – (12 + 2i)?