How do you simplify $(-9x^3yz^2)/(27x^4yz)$ ?

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Answer 1 · 2017-06-12T02:47:04

$(-9x^(3)yz^(2))/(27x^(4)yz)=color(blue)(-z/(3x)$

Simplify:

$(-9x^(3)yz^(2))/(27x^(4)yz)$

Simplify $-9/27$ to $-1/3$ .

$-(x^(3)yz^(2))/(3x^(4)yz)$

Apply quotient exponent rule: $a^m/a^n=a^(m-n)$ .

$-(x^(3-4)y^(1-1)z^(2-1))/3$

Simplify.

$-(x^(-1)y^(0)z^(1))/3$

Apply zero exponent rule: $a^0=1$ .

$-(x^(-1)1z^(1))/3$

Simplify.

$-(x^(-1)z^(1))/3$

Apply negative exponent rule: $a^(-m)=1/a^m$ .

$-z/(3x)$

How do you simplify (-9x^3yz^2)/(27x^4yz)(-9x^3yz^2)/(27x^4yz)?