How do you simplify $(a^2bc)^5(a^2bc^5)$ ?

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Answer 1 · 2015-09-28T19:14:11

$a^12*b^6*c^10$

$(a^10*b^5*c^5)*(a^2*b*c^5)$

$(a^(10+2))(b^(5+1))(c^(5+5))$
= $a^12*b^6*c^10$

Answer 2 · 2015-09-28T19:51:51

The answer is $a^12b^6c^10$ .

$(a^2bc)^5(a^2bc^5)$

Apply the exponent rule $(b^n)^m=b^(n*m)$ .
.
$(a^(2*5)b^(1*5)c^(1*5))(a^2bc^5)=$

$(a^10b^5c^5)(a^2bc^5)$

Remove the parentheses and gather like terms.

$a^10a^2b^5bc^5c^5$

Apply the exponent rule $a^m*a^n=a^(m+n)$

$a^(10+2)b^(5+1)c^(5+5)=$

$a^12b^6c^10$

How do you simplify (a^2bc)^5(a^2bc^5)(a^2bc)^5(a^2bc^5)?