How do you simplify and divide $(x^3-4x^2+5x-6)/(x^2-x+2)$ ?

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Answer 1 · 2017-07-24T11:49:23

$(x-3)$

$(x^3 -4x^2 +5x -6 )/(x^2-x+2)$

$= (x^3- 3x^2 -x^2+3x +2x -6 )/(x^2-x+2)$

$= (x^2(x- 3) -x(x-3) +2(x -3 ))/(x^2-x+2)$

$= ((x- 3) cancel((x^2-x+2)))/cancel((x^2-x+2) )$

$= (x-3)$ [Ans]

How do you simplify and divide (x^3-4x^2+5x-6)/(x^2-x+2)(x^3-4x^2+5x-6)/(x^2-x+2)?