How do you simplify $\frac{b + 4}{2 b^{2} + 5 b - 12}$ $(b+4)/(2b^2+5b-12)$ ?

Question

1593 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-30T21:02:47

$\frac{1}{2 b - 3}$ $1/(2b-3)$

$\frac{b + 4}{2 b^{2} + 5 b - 12}$ $(b+4)/(2b^2+5b-12)$ = $\frac{b + 4}{(2 b - 3) (b + 4)}$ $(b+4)/((2b-3)(b+4))$

The b+4 cancels to leave $\frac{1}{2 b - 3}$ $1/(2b-3)$

How do you simplify (b+4)/(2b^2+5b-12)b+42b2+5b−12(b+4)/(2b^2+5b-12)?