How do you simplify #b^5 • b^4#?
1 Answer
Apr 24, 2016
Explanation:
Notice that for a positive integer
#b^n = overbrace(b * b * ... * b)^"n times"#
So we find:
#b^m * b^n = overbrace(b * b * ... * b)^"m times" * overbrace(b * b * ... * b)^"n times"#
#=overbrace(b * b * ... * b)^"m + n times"#
#=b^(m+n)#
So in particular:
#b^5 * b^4 = b^(5+4) = b^9#