How do you simplify $cos (x - \frac{π}{2})$ $cos(x - pi/2)$ ?

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How do you simplify $cos (x - \frac{π}{2})$ $cos(x - pi/2)$ ?

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Answer 1 · 2016-04-26T19:00:50

$= sin x$ $=sin x$

Explanation:

Use formula: $cos (A - B) = cos A cos B + sin A sin B$ $cos(A-B)=cosAcosB+sinAsinB$

$A = x, B = \frac{π}{2}$ $A=x,B=pi/2$

$cos (x - \frac{π}{2}) = cos x cos (\frac{π}{2}) + sin x sin (\frac{π}{2})$ $cos(x-pi/2)=cosxcos(pi/2)+sinxsin(pi/2)$
$= cos x \cdot 0 + sin x \cdot 1$ $=cosx *0+sinx*1$
$= 0 + sin x$ $=0+sinx$
$= sin x$ $=sin x$

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How do you simplify $cos (x - \frac{π}{2})$ $cos(x - pi/2)$ ?

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